
Question #469ae - Socratic
"Old pH = 4.72"; "New pH = 4.70" > The strategy to follow is a) Write the chemical equation for the buffer. b) Calculate the "pH" of the buffer. c) Calculate the moles of "HCl" added. d) Calculate the …
Question #41282 - Socratic
11 and 16 First, write the problem in the form of a system of equations: 27 = x + y x = 2y - 6 Next, using substitution, combine the two equations replacing x in the first equation with the value of x in the …
Question #23633 - Socratic
You need to know the standard change in entropy as well. The standard change in Gibbs free energy can be calculated using the equation color (blue) (ul (color (black) (DeltaG^@ = DeltaH^@ - T * …
Question #75006 - Socratic
Explanation: Use trig identity: #sec^2 t= (1 + tan^2 t)# In this case: # (2 + 2tan^2 t) + 3tan t - 1 = 0# #2tan^2 t + 3tan t + 1 = 0# Solve this quadratic equation for tan t. Since a - b + c = 0, use shortcut. …
Question #9245f - Socratic
A mole of gasoline will get you 1,303 kcal of energy. If we, somehow, figure out the number of moles of gasoline in 3 gallons, we'd be able to know the answer. Step 1: First of all, there are 11,355 ml in 3 …
Question #e882e - Socratic
See the answer below: Credits: 1. Thanks to the web site www.integral-calculator.com that gave us the direction to be followed to solve this integral! 2. Thanks to the website www.symbolab.com that …
Mass ratios problem? - Socratic
Nov 4, 2017 · The nickel:zinc:copper ratio of 3:4:13 tells us that XXX for every 3 units of nickel, XXX there will be 4 units of zinc, and XXX there will be 13 units of copper. That is, out of a total of 3 +4 + …
Question #7c39a - Socratic
Feb 11, 2018 · (1,1.5) Let's rewrite this into form 4p (y-k)= (x-h)^2 y=1/2 (x-1)^2+1 =>y-1=1/2 (x-1)^2 =>2 (y-1)= (x-1)^2 We now compare this to 4p (y-k)= (x-h)^2 2 (y-1)= (x-1)^2 4p (y-k)= (x-h)^2 It …
Question #606b9 - Socratic
May 7, 2016 · Given tax rate imposed ( 2nd line down in question) on income over $20700 and less than $38000.
Question #ed7f1 - Socratic
Feb 12, 2016 · Atomic size decreases across the period because of EFFECTIVE NUCLEAR CHARGE. As you add on more and more electrons, you also add on more and more protons. Because of this, …